Y=2x^2+2x+43

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Solution for Y=2x^2+2x+43 equation: 



=2Y^2+2Y+43

We move all terms to the left:

-(2Y^2+2Y+43)=0

We get rid of parentheses

-2Y^2-2Y-43=0

a = -2; b = -2; c = -43;
Δ = b2-4ac
Δ = -22-4·(-2)·(-43)
Δ = -340
Delta is less than zero, so there is no solution for the equation

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